3.567 \(\int \frac{x^{11} \sqrt [3]{a+b x^3}}{a d-b d x^3} \, dx\)

Optimal. Leaf size=220 \[ -\frac{a^3 \sqrt [3]{a+b x^3}}{b^4 d}-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a^{10/3} \log \left (a-b x^3\right )}{3\ 2^{2/3} b^4 d}-\frac{a^{10/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{2^{2/3} b^4 d}+\frac{\sqrt [3]{2} a^{10/3} \tan ^{-1}\left (\frac{2^{2/3} \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt{3} \sqrt [3]{a}}\right )}{\sqrt{3} b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d} \]

[Out]

-((a^3*(a + b*x^3)^(1/3))/(b^4*d)) - (a^2*(a + b*x^3)^(4/3))/(4*b^4*d) + (a*(a + b*x^3)^(7/3))/(7*b^4*d) - (a
+ b*x^3)^(10/3)/(10*b^4*d) + (2^(1/3)*a^(10/3)*ArcTan[(a^(1/3) + 2^(2/3)*(a + b*x^3)^(1/3))/(Sqrt[3]*a^(1/3))]
)/(Sqrt[3]*b^4*d) + (a^(10/3)*Log[a - b*x^3])/(3*2^(2/3)*b^4*d) - (a^(10/3)*Log[2^(1/3)*a^(1/3) - (a + b*x^3)^
(1/3)])/(2^(2/3)*b^4*d)

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Rubi [A]  time = 0.235602, antiderivative size = 220, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {446, 88, 50, 57, 617, 204, 31} \[ -\frac{a^3 \sqrt [3]{a+b x^3}}{b^4 d}-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a^{10/3} \log \left (a-b x^3\right )}{3\ 2^{2/3} b^4 d}-\frac{a^{10/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{2^{2/3} b^4 d}+\frac{\sqrt [3]{2} a^{10/3} \tan ^{-1}\left (\frac{2^{2/3} \sqrt [3]{a+b x^3}+\sqrt [3]{a}}{\sqrt{3} \sqrt [3]{a}}\right )}{\sqrt{3} b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d} \]

Antiderivative was successfully verified.

[In]

Int[(x^11*(a + b*x^3)^(1/3))/(a*d - b*d*x^3),x]

[Out]

-((a^3*(a + b*x^3)^(1/3))/(b^4*d)) - (a^2*(a + b*x^3)^(4/3))/(4*b^4*d) + (a*(a + b*x^3)^(7/3))/(7*b^4*d) - (a
+ b*x^3)^(10/3)/(10*b^4*d) + (2^(1/3)*a^(10/3)*ArcTan[(a^(1/3) + 2^(2/3)*(a + b*x^3)^(1/3))/(Sqrt[3]*a^(1/3))]
)/(Sqrt[3]*b^4*d) + (a^(10/3)*Log[a - b*x^3])/(3*2^(2/3)*b^4*d) - (a^(10/3)*Log[2^(1/3)*a^(1/3) - (a + b*x^3)^
(1/3)])/(2^(2/3)*b^4*d)

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 57

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(2/3)), x_Symbol] :> With[{q = Rt[(b*c - a*d)/b, 3]}, -Simp[L
og[RemoveContent[a + b*x, x]]/(2*b*q^2), x] + (-Dist[3/(2*b*q), Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x
)^(1/3)], x] - Dist[3/(2*b*q^2), Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x]
&& PosQ[(b*c - a*d)/b]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rubi steps

\begin{align*} \int \frac{x^{11} \sqrt [3]{a+b x^3}}{a d-b d x^3} \, dx &=\frac{1}{3} \operatorname{Subst}\left (\int \frac{x^3 \sqrt [3]{a+b x}}{a d-b d x} \, dx,x,x^3\right )\\ &=\frac{1}{3} \operatorname{Subst}\left (\int \left (-\frac{a^2 \sqrt [3]{a+b x}}{b^3 d}+\frac{a (a+b x)^{4/3}}{b^3 d}-\frac{(a+b x)^{7/3}}{b^3 d}+\frac{a^3 \sqrt [3]{a+b x}}{b^3 (a d-b d x)}\right ) \, dx,x,x^3\right )\\ &=-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d}+\frac{a^3 \operatorname{Subst}\left (\int \frac{\sqrt [3]{a+b x}}{a d-b d x} \, dx,x,x^3\right )}{3 b^3}\\ &=-\frac{a^3 \sqrt [3]{a+b x^3}}{b^4 d}-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d}+\frac{\left (2 a^4\right ) \operatorname{Subst}\left (\int \frac{1}{(a+b x)^{2/3} (a d-b d x)} \, dx,x,x^3\right )}{3 b^3}\\ &=-\frac{a^3 \sqrt [3]{a+b x^3}}{b^4 d}-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d}+\frac{a^{10/3} \log \left (a-b x^3\right )}{3\ 2^{2/3} b^4 d}+\frac{a^{10/3} \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{2} \sqrt [3]{a}-x} \, dx,x,\sqrt [3]{a+b x^3}\right )}{2^{2/3} b^4 d}+\frac{a^{11/3} \operatorname{Subst}\left (\int \frac{1}{2^{2/3} a^{2/3}+\sqrt [3]{2} \sqrt [3]{a} x+x^2} \, dx,x,\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} b^4 d}\\ &=-\frac{a^3 \sqrt [3]{a+b x^3}}{b^4 d}-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d}+\frac{a^{10/3} \log \left (a-b x^3\right )}{3\ 2^{2/3} b^4 d}-\frac{a^{10/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{2^{2/3} b^4 d}-\frac{\left (\sqrt [3]{2} a^{10/3}\right ) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}\right )}{b^4 d}\\ &=-\frac{a^3 \sqrt [3]{a+b x^3}}{b^4 d}-\frac{a^2 \left (a+b x^3\right )^{4/3}}{4 b^4 d}+\frac{a \left (a+b x^3\right )^{7/3}}{7 b^4 d}-\frac{\left (a+b x^3\right )^{10/3}}{10 b^4 d}+\frac{\sqrt [3]{2} a^{10/3} \tan ^{-1}\left (\frac{1+\frac{2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}}{\sqrt{3}}\right )}{\sqrt{3} b^4 d}+\frac{a^{10/3} \log \left (a-b x^3\right )}{3\ 2^{2/3} b^4 d}-\frac{a^{10/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )}{2^{2/3} b^4 d}\\ \end{align*}

Mathematica [A]  time = 0.196546, size = 230, normalized size = 1.05 \[ -\frac{111 a^2 b x^3 \sqrt [3]{a+b x^3}+507 a^3 \sqrt [3]{a+b x^3}+140 \sqrt [3]{2} a^{10/3} \log \left (\sqrt [3]{2} \sqrt [3]{a}-\sqrt [3]{a+b x^3}\right )-70 \sqrt [3]{2} a^{10/3} \log \left (2^{2/3} a^{2/3}+\sqrt [3]{2} \sqrt [3]{a} \sqrt [3]{a+b x^3}+\left (a+b x^3\right )^{2/3}\right )-140 \sqrt [3]{2} \sqrt{3} a^{10/3} \tan ^{-1}\left (\frac{\frac{2^{2/3} \sqrt [3]{a+b x^3}}{\sqrt [3]{a}}+1}{\sqrt{3}}\right )+42 b^3 x^9 \sqrt [3]{a+b x^3}+66 a b^2 x^6 \sqrt [3]{a+b x^3}}{420 b^4 d} \]

Antiderivative was successfully verified.

[In]

Integrate[(x^11*(a + b*x^3)^(1/3))/(a*d - b*d*x^3),x]

[Out]

-(507*a^3*(a + b*x^3)^(1/3) + 111*a^2*b*x^3*(a + b*x^3)^(1/3) + 66*a*b^2*x^6*(a + b*x^3)^(1/3) + 42*b^3*x^9*(a
+ b*x^3)^(1/3) - 140*2^(1/3)*Sqrt[3]*a^(10/3)*ArcTan[(1 + (2^(2/3)*(a + b*x^3)^(1/3))/a^(1/3))/Sqrt[3]] + 140
*2^(1/3)*a^(10/3)*Log[2^(1/3)*a^(1/3) - (a + b*x^3)^(1/3)] - 70*2^(1/3)*a^(10/3)*Log[2^(2/3)*a^(2/3) + 2^(1/3)
*a^(1/3)*(a + b*x^3)^(1/3) + (a + b*x^3)^(2/3)])/(420*b^4*d)

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Maple [F]  time = 0.063, size = 0, normalized size = 0. \begin{align*} \int{\frac{{x}^{11}}{-bd{x}^{3}+ad}\sqrt [3]{b{x}^{3}+a}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^11*(b*x^3+a)^(1/3)/(-b*d*x^3+a*d),x)

[Out]

int(x^11*(b*x^3+a)^(1/3)/(-b*d*x^3+a*d),x)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(b*x^3+a)^(1/3)/(-b*d*x^3+a*d),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 1.34805, size = 520, normalized size = 2.36 \begin{align*} -\frac{140 \, \sqrt{3} 2^{\frac{1}{3}} \left (-a\right )^{\frac{1}{3}} a^{3} \arctan \left (\frac{\sqrt{3} 2^{\frac{2}{3}}{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-a\right )^{\frac{2}{3}} + \sqrt{3} a}{3 \, a}\right ) + 70 \cdot 2^{\frac{1}{3}} \left (-a\right )^{\frac{1}{3}} a^{3} \log \left (2^{\frac{2}{3}} \left (-a\right )^{\frac{2}{3}} - 2^{\frac{1}{3}}{\left (b x^{3} + a\right )}^{\frac{1}{3}} \left (-a\right )^{\frac{1}{3}} +{\left (b x^{3} + a\right )}^{\frac{2}{3}}\right ) - 140 \cdot 2^{\frac{1}{3}} \left (-a\right )^{\frac{1}{3}} a^{3} \log \left (2^{\frac{1}{3}} \left (-a\right )^{\frac{1}{3}} +{\left (b x^{3} + a\right )}^{\frac{1}{3}}\right ) + 3 \,{\left (14 \, b^{3} x^{9} + 22 \, a b^{2} x^{6} + 37 \, a^{2} b x^{3} + 169 \, a^{3}\right )}{\left (b x^{3} + a\right )}^{\frac{1}{3}}}{420 \, b^{4} d} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(b*x^3+a)^(1/3)/(-b*d*x^3+a*d),x, algorithm="fricas")

[Out]

-1/420*(140*sqrt(3)*2^(1/3)*(-a)^(1/3)*a^3*arctan(1/3*(sqrt(3)*2^(2/3)*(b*x^3 + a)^(1/3)*(-a)^(2/3) + sqrt(3)*
a)/a) + 70*2^(1/3)*(-a)^(1/3)*a^3*log(2^(2/3)*(-a)^(2/3) - 2^(1/3)*(b*x^3 + a)^(1/3)*(-a)^(1/3) + (b*x^3 + a)^
(2/3)) - 140*2^(1/3)*(-a)^(1/3)*a^3*log(2^(1/3)*(-a)^(1/3) + (b*x^3 + a)^(1/3)) + 3*(14*b^3*x^9 + 22*a*b^2*x^6
+ 37*a^2*b*x^3 + 169*a^3)*(b*x^3 + a)^(1/3))/(b^4*d)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**11*(b*x**3+a)**(1/3)/(-b*d*x**3+a*d),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \mathit{sage}_{0} x \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^11*(b*x^3+a)^(1/3)/(-b*d*x^3+a*d),x, algorithm="giac")

[Out]

sage0*x